1 solutions

  • 0
    @ 2025-11-5 17:18:31

    C :

    #include <stdio.h>
    int f(int n)
    {
    	int sum;
    	if(n==1)
    	return 1;
    	if(n==2)
    	return 2;
    	else
    	sum=f(n-1)+f(n-2);
    	return sum;
    }
    int main()
    {
    	int n;
    	while(scanf("%d",&n)!=EOF)
    	{
    		printf("%d\n",f(n));
    	}
    	return 0;
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;int d[35];
    	d[0]=1,d[1]=1;
    	for (int i=2;i<=30;i++) d[i]=d[i-1]+d[i-2];
    	while(~scanf("%d",&n)){
    		printf("%d\n",d[n]);
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    18278
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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