1 solutions
-
0
C :
#include <stdio.h> int main() { int n,a[10000],i,j,sum; while(scanf("%d",&n)!=EOF) { sum=0; for(i=0;i<n;i++) scanf("%d",&a[i]); for(i=0;i<n;i++) { if(a[i]==100) sum+=1; if(a[i]==200) sum+=2; } if(sum%2==0) printf("Yes\n"); else printf("No\n"); } return 0; }C++ :
#include <bits/stdc++.h> using namespace std; int cmp(int a,int b) { return a>b; } int main() { int n; while(~scanf("%d",&n)){ int a[105]; int sum=0; int one=0; for (int i=0;i<n;i++){ scanf("%d",&a[i]); a[i]=a[i]/100; sum+=a[i]; if (a[i]==1) one++; } int avr=sum/2; if (avr!=sum-avr){ printf("No\n"); continue; } sort(a,a+n,cmp); int ss=0; while(avr>=a[ss]&&a[ss]==2){ avr-=a[ss]; ss++; } if (avr<=one) printf("Yes\n"); else printf("No\n"); } return 0; }
- 1
Information
- ID
- 18266
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By