1 solutions

  • 0
    @ 2025-11-5 17:17:48

    C :

    #include <stdio.h>
    int a[1000001];
    int max(int a,int b)
    {
    	if(a>b)
    	return a;
    	else
    	return b;
    }
    int min(int a,int b)
    {
    	if(a<b)
    	return a;
    	else
    	return b;
    }
    int main()
    {
    	int t,n,l,i,j,Min,Max;
    	while(scanf("%d",&t)!=EOF)
    	{
    		for(i=1;i<=t;i++)
    		{
    			Min=Max=-1;
    			scanf("%d%d",&l,&n);
    			for(j=0;j<n;j++)
    			scanf("%d",&a[j]);
    			for(j=0;j<n;j++)
    			{
    				Min=max(Min,min(a[j],l-a[j]));
    				Max=max(Max,max(a[j],l-a[j]));
    			}
    			printf("%d %d\n",Min,Max);
    		}
    	}
    	return 0;
    }
    

    C++ :

    #include<string.h>  
    #include<stdio.h>  
    #include<stdlib.h>  
    #include<iostream>  
    #include<vector>  
    #include<algorithm>  
    using namespace std;  
    int a[1000000+5];
    int maxx(int a,int b){
    	if(a > b) return a;
    	else return b;
    }
    int minn(int a,int b){
    	if(a > b) return b;
    	else return a;
    }
    int main(){
    	int t;
    	while(scanf("%d",&t)!=EOF){
    		while(t--){
    			int l,n;
    			scanf("%d%d",&l,&n);
    			for(int i = 0;i < n;i++)
    				scanf("%d",&a[i]);
    			int max = 0,min =0;
    			for(int i = 0;i < n;i++){
    				int t;
    				t = minn(l - a[i],a[i]);
    				if(t > max) max = t;
    			}
    			for(int i = 0;i < n;i++){
    				int t;
    				t = maxx(l - a[i],a[i]);
    				if(t > min) min = t;
    			}
    			printf("%d %d\n",max,min);
    		}		
    	}
    	return 0;
    }
    
    
    • 1

    Information

    ID
    18264
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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