1 solutions

  • 0
    @ 2025-11-5 20:15:58

    C :

    #include<stdio.h>
    int main()
    {
        int i, j, n, a, b, s;
        scanf("%d", &n);
        while(n--)
        {
            scanf("%d%d", &a, &b);
            s = 1;
            for(i=0; i<b; i++)
            {
                s = (a%1000 * s)%1000;
            }
            printf("%d\n", s);
        }
        return 0;
    }
    
    

    C++ :

    #include <cstdio>
    #include <cstring>
    #include <cmath>
    
    using namespace std ;
    
    int num[10000] ;
    
    int abs( int a ) {
        if( a < 0 ) return -a ;
        return a ;
    }
    
    int main() {
    
        int n ;
        scanf("%d"  ,&n ) ;
        while( n -- ) {
    
            int a , b ;
            scanf("%d%d" , &a , &b ) ;
            int res = 1 ;
            for( int i = 0 ; i < b ; i ++ ) {
                res = ( res * a ) % 1000 ;
            }
            printf("%d\n" , res ) ;
        }
    
        return 0 ;
    }
    
    
    • 1

    Information

    ID
    20201
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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