1 solutions

  • 0
    @ 2025-11-5 20:15:07

    C++ :

    #include <iostream>
    #include <vector>
    
    using namespace std;
    
    
    void Process(int n)
    {
    	int sum;
    
    	vector<int>v;	
    
    	v.push_back(1);
    	
    	for (int i = 2; i <= n; i++)
    	{
    		sum = 0;
    		for (int j = 0; j < v.size(); j++)
    		{
    			sum = v[j] * i + sum;
    			v[j] = sum %10;
    			sum = sum /10;
    		}
    		
    		while (sum >0)
    		{
    			v.push_back(sum%10);
    			sum = sum /10;
    		}
    	}
    
    	vector<int>::reverse_iterator rit;//倒转输出阶乘数值
    	for (rit=v.rbegin(); rit!=v.rend(); rit++)
    		cout<<*rit;	
    }
    
    
    int main()
    {
    	int n;
    	while (cin>>n)
    	{
    		Process(n);
    		cout<<endl;
    	}
        return 0;
    }
    
    

    Java :

    import java.util.*;
    import java.math.BigInteger;
    public class Main{
        public static void main(String[] args){
            Scanner input = new Scanner(System.in);
            while(input.hasNextInt()){
                int n = input.nextInt();
                String a = "2";
                String b = "1";
                for(int i = 1;i < n;i++){
                    b = xx(b,a);
                    a = yy(a,"1");
                }
                System.out.println(b);
            }
        }
        public static String xx(String x,String y){
            BigInteger result=null;
            BigInteger bigX=new BigInteger(x);
            BigInteger bigY=new BigInteger(y);
            result=bigX.multiply(bigY);
            return result.toString();
        }
        public static String yy(String x,String y){
            BigInteger result=null;
            BigInteger X=new BigInteger(x);
            BigInteger bb= new BigInteger(y);
            result = X.add(bb);
            return result.toString();
        }
    }
    
    • 1

    Information

    ID
    20183
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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