1 solutions

  • 0
    @ 2025-11-5 19:59:46

    C :

    #include<stdio.h>
    
    int main()
    {
      int a[10];
      int t,i,count=0;
      for(i=0;i<10;i++)
    	  scanf("%d",&a[i]);
      scanf("%d",&t);
      for(i=0;i<10;i++)
      {
          if(t+30>=a[i])
    		  count++;
      }
      printf("%d\n",count);
      return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int a[10],b;
    	for(int i=0;i<10;i++)
    		cin>>a[i];
    	cin>>b;
    	int count=0;
    	for(int i=0;i<10;i++)
    	{
    		if(a[i]<=b+30)
    			count++;
    	}
    	cout<<count<<endl;
    	return 0;
    }
    

    Pascal :

    var
    i,n,s:integer;
    a:array[1..10] of integer;
    begin
      for i:=1 to 10 do read(a[i]);
      read(n);
      s:=0;
      for i:=1 to 10 do
        if n+30>=a[i] then s:=s+1;
      write(s);
    end.
    
    • 1

    Information

    ID
    19917
    Time
    1000ms
    Memory
    125MiB
    Difficulty
    (None)
    Tags
    # Submissions
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