1 solutions
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0
C :
#include<stdio.h> int main() { int a[10]; int t,i,count=0; for(i=0;i<10;i++) scanf("%d",&a[i]); scanf("%d",&t); for(i=0;i<10;i++) { if(t+30>=a[i]) count++; } printf("%d\n",count); return 0; }C++ :
#include<iostream> using namespace std; int main() { int a[10],b; for(int i=0;i<10;i++) cin>>a[i]; cin>>b; int count=0; for(int i=0;i<10;i++) { if(a[i]<=b+30) count++; } cout<<count<<endl; return 0; }Pascal :
var i,n,s:integer; a:array[1..10] of integer; begin for i:=1 to 10 do read(a[i]); read(n); s:=0; for i:=1 to 10 do if n+30>=a[i] then s:=s+1; write(s); end.
- 1
Information
- ID
- 19917
- Time
- 1000ms
- Memory
- 125MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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