1 solutions
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0
C :
#include<stdio.h> #include<math.h> int main() { int n; while(scanf("%d",&n)!=EOF) printf("%d\n",(int)pow(10,n*log10(n)-(int)(n*log10(n)))); return 0; }C++ :
#include<stdio.h> #include<math.h> int main() { int n; while(scanf("%d",&n)!=EOF) printf("%d\n",(int)pow(10,n*log10(n)-(int)(n*log10(n)))); return 0; }Java :
public class Main { public static void main(String[] args) { java.util.Scanner input = new java.util.Scanner(System.in) ; while(input.hasNextInt()){ int n =input.nextInt(); double x = n*Math.log10(n); double m = x-(int)x; int m1=(int)Math.pow(10,m); System.out.println(m1); } } }Python :
from math import * while True: try: n = int(raw_input()) print int(modf(10**(modf(n*log10(n))[0]))[1]) except: break
- 1
Information
- ID
- 19826
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
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