1 solutions
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0
C :
#include<stdio.h> int main() { double sum; int n,i,a[100]; while(scanf("%d",&n)!=EOF) { sum=0; for(i=0;i<n;i++) { scanf("%d",&a[i]); sum+=a[i]; } printf("%.2lf\n",sum/n); } return 0; }C++ :
#include <iostream> #include <iomanip> using namespace std; int main() { int n; int a[100]; while (cin>>n&&1<=n&&n<=100) { int i; double sum=0; for (i=0;i<n;i++) { cin>>a[i]; sum+=a[i]; } sum/=i; cout<<setiosflags(ios::fixed)<<setprecision(2)<<sum<<endl; } return 0; }Pascal :
var i,j,k,l,n,m:longint; begin while not eof do begin readln(n); k:=0; for i:=1 to n do begin readln(m); k:=k+m; end; writeln(k/n:0:2); end; end.
- 1
Information
- ID
- 19811
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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