1 solutions

  • 0
    @ 2025-11-5 19:54:29

    C :

    #include<stdio.h>
    int main()
    {   
    	double sum;
    	int n,i,a[100];
        while(scanf("%d",&n)!=EOF)
    	{
    		sum=0;
    		for(i=0;i<n;i++)
    		{
    			scanf("%d",&a[i]);
    			sum+=a[i];
    		}
    		printf("%.2lf\n",sum/n);
    	}   
    	return 0;
    }
    
    
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    int main()
    {
            int n;
            int a[100];
            while (cin>>n&&1<=n&&n<=100)
            {
                    int i;
                    double sum=0;
                    for (i=0;i<n;i++)
                    {
                            cin>>a[i];
                            sum+=a[i];
                    }
                    sum/=i;
                    cout<<setiosflags(ios::fixed)<<setprecision(2)<<sum<<endl;
            }
            return 0;
    }
    

    Pascal :

    var i,j,k,l,n,m:longint;
    begin
    while not eof do
    begin
    readln(n);
    k:=0; 
    for i:=1 to n do
    begin
    readln(m);
    k:=k+m;
    end;
    writeln(k/n:0:2);
    end;
    end.
    
    • 1

    Information

    ID
    19811
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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