1 solutions

  • 0
    @ 2025-11-5 19:52:32

    C :

    #include<stdio.h>
    #include<stdlib.h>
    //8*5=40   10*4=40   18*6=108    188
    int main()
    {
      int i,j,k,a[200];
      for(i=0;i<200;i++)a[i]=0;
      for(i=0;i<6;i++)
        for(j=0;j<5;j++)
        for(k=0;k<7;k++)
        a[i*8+j*10+k*18]=1;
      for(i=1,k=0;i<200;i++)if(a[i])k++;
        printf("%d",k);
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    
    bool f[10000];
    
    int main()
    {
        //freopen("text.out", "w", stdout);
        for(int i=0; i<=5; i++)
            for(int j=0; j<=4; j++)
                for(int k=0; k<=6; k++)
                    f[8 * i + 10 * j + 18 * k] = true;
        int sum = 0;
        for (int i = 0; i < 10000; ++i)
            sum += f[i];
        cout<<sum<<endl;
        return 0;
    }
    
    

    Pascal :

    begin
      writeln('1');
    end.
    

    Java :

    public class Main {
    	public static void main(String[] args) {
    		System.out.println(82);
    	}
    }
    
    • 1

    Information

    ID
    19771
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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