1 solutions
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0
C :
#include <stdio.h> int main() { long sum, n; int i; sum = 0; n = 1; for(i = 0; i < 30; i++) { sum += n; n *= 2; } printf("%ld %ld\n", sum / 100, 10*10000*30); return 0; }C++ :
#include<stdio.h> #include<math.h> int main() { long int a=1,i; for(i=1;i<30;i++) a+=pow(2,i); printf("%ld %ld\n",a/100,10*30*10000); return 0; }Java :
public class Main { public static void main(String[] args) { int i; long s=0; for(i=0;i<30;i++) { s=2*s+1; } s=s/100; System.out.println(s+" 3000000"); } }Python :
# coding=utf-8 a=100000*30 b=0.01 s=0 for i in range(1,31): s=s+b b=b*2 print("%d %d"%(s,a))
- 1
Information
- ID
- 19729
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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