1 solutions

  • 0
    @ 2025-11-5 19:50:20

    C :

    #include <stdio.h>
    int main()
    {
    	long sum, n;
    	int i;
    	sum = 0;
    	n = 1;
    	for(i = 0; i < 30; i++)
    	{
    		sum += n;
    		n *= 2;
    	}
    	printf("%ld %ld\n", sum / 100, 10*10000*30);
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    #include<math.h>
    
    int main()
    {
    	long int a=1,i;
    	for(i=1;i<30;i++)
    		a+=pow(2,i);
    	printf("%ld %ld\n",a/100,10*30*10000);
    	return 0;
    }
    

    Java :

    public class Main {
    	public static void main(String[] args) {
    			int i;
    			long s=0;
    			
    			for(i=0;i<30;i++) {
    				s=2*s+1;
    			}
    			s=s/100;
    			
    			System.out.println(s+" 3000000");
    			
         }
    }
    

    Python :

    # coding=utf-8
    a=100000*30
    b=0.01
    s=0
    for i in range(1,31):
        s=s+b
        b=b*2
    print("%d %d"%(s,a))
    
    • 1

    Information

    ID
    19729
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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