1 solutions
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0
C :
#include <stdio.h> int main(void) { int c[10],i; float p; for (i=0;i<10;i++) { scanf("%d",&c[i]); p+=c[i]; } p=p/10; printf("%.1f\n",p); for (i=0;i<10;i++) { if (c[i]>p) printf("%d ",c[i]); } return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { int a[11],sum=0; for (int i=1; i<=10; i++) { cin>>a[i]; sum+=a[i]; } double ave=sum/10.0; printf("%.1lf\n",ave); for (int i=1; i<=10; i++) if (a[i]>ave) cout<<a[i]<<" "; cout<<endl; return 0; }
- 1
Information
- ID
- 19666
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By