1 solutions
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0
C :
#include <stdio.h> double total(int n); int main() { int n; scanf("%d",&n); printf("%.3lf\n",total(n)); return 0; } double total(int n) { double i,sum; for (i=1;i<=n;i++) { sum+=1/i; } return sum; }C++ :
#include<iostream> #include<cstdio> using namespace std; double total(int n) { double s=0; for (int i=1; i<=n; i++) s+=1.0/i; return s; } int main() { int n; cin>>n; printf("%.3lf\n",total(n)); return 0; }
- 1
Information
- ID
- 19664
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By