1 solutions

  • 0
    @ 2025-11-5 19:46:54

    C :

    #include <stdio.h>
    int ctof(int c);
    
    int main(void)
    {
    	int i,start,end;
        scanf("%d%d",&start,&end);
        for(i=start;i<=end;i+=10)
    	{
        	printf("%dC=%dF\n",i,ctof(i));
        }
    	return 0;
    }
    
    int ctof(int c)
    {
    	return 32+c*9/5;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int a,b,f;
    	cin>>a>>b;
    	for (int i=a; i<=b; i+=10)
    	{
    		f=32+i*9.0/5;
    		cout<<i<<"C="<<f<<"F\n";
    	}
    	return 0;
    }
    
    • 1

    《C语言程序设计》江宝钏主编-习题6-1-温度转换

    Information

    ID
    19662
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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