1 solutions

  • 0
    @ 2025-11-5 19:46:39

    C :

    #include <stdio.h>
    int main(void)
    {
    	int a[20],i,x;
    	float j;
    	for (i=0;i<20;i++)
    	{
    		scanf("%d",&a[i]);
    		if (a[i]<0)
    		x+=1;
    		j+=a[i];
    	}
    	printf("%d %.1f",x,j/20);
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int x,t=0;
    	double sum=0;
    	for (int i=1; i<=20; i++)
    	{
    		cin>>x;
    		if (x<0) t++;
    		sum+=x;
    	}
    	printf("%d %.1lf\n",t,sum/20);
    	return 0;
    }
    
    • 1

    《C语言程序设计》江宝钏主编-习题5-1-统计整数

    Information

    ID
    19657
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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