1 solutions
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0
C :
#include <stdio.h> int main(void) { int a[20],i,x; float j; for (i=0;i<20;i++) { scanf("%d",&a[i]); if (a[i]<0) x+=1; j+=a[i]; } printf("%d %.1f",x,j/20); return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { int x,t=0; double sum=0; for (int i=1; i<=20; i++) { cin>>x; if (x<0) t++; sum+=x; } printf("%d %.1lf\n",t,sum/20); return 0; }
- 1
Information
- ID
- 19657
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By