1 solutions

  • 0
    @ 2025-11-5 19:46:26

    C :

    #include <stdio.h>
    int main(void)
    {
    	int x,y;
    	scanf ("%d",&x);
    	if (x<=5)
    	{
    		y=x*x+3*x-4;
    	}
    	else if (x>5)
    	{
    		y=x*x-5*x+7;
    	}
    	printf("%d",y);
    	return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int x,y;
    	cin>>x;
    	if (x<=5) y=x*x+3*x-4;
    	else y=x*x-5*x+7;
    	cout<<y<<endl;
    	return 0;
    }
    
    • 1

    《C语言程序设计》江宝钏主编-习题4-2-分段函数

    Information

    ID
    19653
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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