1 solutions
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0
C :
#include <stdio.h> int main(void) { int x,y; scanf ("%d",&x); if (x<=5) { y=x*x+3*x-4; } else if (x>5) { y=x*x-5*x+7; } printf("%d",y); return 0; }C++ :
#include<iostream> using namespace std; int main() { int x,y; cin>>x; if (x<=5) y=x*x+3*x-4; else y=x*x-5*x+7; cout<<y<<endl; return 0; }
- 1
Information
- ID
- 19653
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By