1 solutions

  • 0
    @ 2025-11-5 19:46:23

    C :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
    	int year;
    	float money,rate,sum;
    	sum=0;
    	scanf("%f%d%f",&money,&year,&rate);
    	sum=money*pow((1+rate),year);
    	printf("%.1f\n",sum);
    	return 0;
    }
    

    C++ :

    #include "stdio.h"
    #include "math.h"
    int main(int argc, char* argv[])
    {
    	double m,y,r,sum;
    	while(~scanf("%lf%lf%lf",&m,&y,&r))
    	{
    	  sum=m*pow((1+r),y);
    	  printf("%.1lf\n",sum);
    	}
    	return 0;
    }
    
    
    • 1

    《C语言程序设计》江宝钏主编-习题3-9-利滚利

    Information

    ID
    19652
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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