1 solutions
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0
C :
#include<stdio.h> int main() { int T,i,n,sum,j=1,a[21],b[21]; scanf("%d",&T); while(j<=T) { sum=0; scanf("%d",&n); for(i=0;i<n;i++) scanf("%d",&a[i]); for(i=0;i<n-1;i++) sum+=(a[i]-1); sum=sum+a[n-1]; b[j++]=sum; } for(i=1;i<=T;i++) printf("Case %d#: %d\n",i,b[i]); return 0; }
- 1
Information
- ID
- 19637
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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