1 solutions

  • 0
    @ 2025-11-5 19:45:37

    C :

    #include<stdio.h>
    int main()
    {
    	int T,i,n,sum,j=1,a[21],b[21];
    	scanf("%d",&T);
    	while(j<=T)
    	{
    		sum=0;
    		scanf("%d",&n);
    		for(i=0;i<n;i++)
    			scanf("%d",&a[i]);
    		for(i=0;i<n-1;i++)
    			sum+=(a[i]-1);
    		sum=sum+a[n-1];
    		b[j++]=sum;
    	}
    	for(i=1;i<=T;i++)
    		printf("Case %d#: %d\n",i,b[i]);
    	return 0;
    }
    
    • 1

    Information

    ID
    19637
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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