1 solutions
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0
C :
int main(int argc, char* argv[]) { char c; while(~scanf("%c%*c",&c)) { printf("%c\n",c+32); } return 0; }C++ :
#include<iostream> using namespace std; int main() { char a,b; int d,e; cin>>a; d=(int)a; //大写字母减肥记 //非大写字母减肥记 d=d+32; cout<<(char)d<<endl; }Pascal :
Program TK1875; var a:char; Begin read(a); writeln(chr(ord(a)+32)); End.
- 1
Information
- ID
- 19621
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
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