1 solutions
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0
C :
int main(int argc, char* argv[]) { int a,b; while(~scanf("%d%d",&a,&b)) { printf("%.1lf\n",(5-3*b)*1.0/(2*a)); } return 0; }C++ :
#include <iostream> #include<iomanip> using namespace std; int main() { int a,b; double x; cin>>a>>b; x=(5-3*b)*1.0/(2*a); cout<<fixed<<setprecision(1); cout<<x<<endl; return 0; }
- 1
Information
- ID
- 19610
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By