1 solutions
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0
C :
#include<stdio.h> int main(){ int n,k,t,sum=0,max,min; while(scanf("%d",&n)!=EOF){ k=n; sum=0; while(n--){ scanf("%d",&t); if(n==k-1){ min=t; max=t; } if(t<min) min=t; if(t>max) max=t; sum=sum+t; } printf("%.2lf\n",(double)(sum-min-max)/(k-2)); } return 0; }
- 1
Information
- ID
- 19578
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By