1 solutions

  • 0
    @ 2025-11-5 19:42:47

    C :

    #include<stdio.h>
    
    int main(){ 
    	int n,k,t,sum=0,max,min;
    	while(scanf("%d",&n)!=EOF){
    		k=n;
    		sum=0;
    		while(n--){
    			scanf("%d",&t);
    			if(n==k-1){
    				min=t;
    				max=t;
    			}
    			if(t<min) min=t;
    			if(t>max) max=t;
    			sum=sum+t;
    		}
    		printf("%.2lf\n",(double)(sum-min-max)/(k-2));
    	}
    
    	return 0; 
    }
    
    • 1

    Information

    ID
    19578
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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