1 solutions
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0
C++ :
#include<iostream> using namespace std; int main(){ int i,n,m,ave; while(scanf("%d %d",&n,&m)!=EOF&&n<=100){ if((n%m)!=0){ for(i=1;i<=(n/m);i++){ ave=(2*i-1)*m+1; cout<<ave; cout<<" "; } cout<<(i-1)*m+n+1<<endl; } else{ for(i=1;i<(n/m);i++){ ave=(2*i-1)*m+1; cout<<ave; cout<<" "; } cout<<(2*i-1)*m+1<<endl; } } return 0; }
- 1
Information
- ID
- 19545
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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