1 solutions

  • 0
    @ 2025-11-5 19:39:43

    C :

    #include <stdio.h>
    int main(int argc, char *argv[])
    {
    	int n,year;
    	while(scanf("%d",&year)!=EOF)
    	{
    		if(year<=2033&&year>=2014)
    		{
    			if(year==2024||year==2028||year==2032)
    			printf("6\n");
    			else
    			printf("7\n");
    		}
    	}
    	return 0;
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    int main(int argc, char *argv[])
    {
    	int n;
    	while(cin>>n){
    		n%=100;
    		int ans=(int)(n*0.2422 + 7.18) - n /4;
    
    		cout<<ans<<endl;
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    19513
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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