1 solutions
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0
C :
#include <stdio.h> int main(int argc, char *argv[]) { int n,year; while(scanf("%d",&year)!=EOF) { if(year<=2033&&year>=2014) { if(year==2024||year==2028||year==2032) printf("6\n"); else printf("7\n"); } } return 0; }C++ :
#include <iostream> using namespace std; int main(int argc, char *argv[]) { int n; while(cin>>n){ n%=100; int ans=(int)(n*0.2422 + 7.18) - n /4; cout<<ans<<endl; } return 0; }
- 1
Information
- ID
- 19513
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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