1 solutions

  • 0
    @ 2025-11-5 19:39:35

    C :

    #include <stdio.h>
    main(){
    	int n,i=1,j=0,k=0,a[1000]={0};
    	scanf("%d",&n);
    	while(j<n-1){
    		if(i==3&&a[k]==0){a[k]=1;j++;}
    		k++;if(k==n)k%=n;
    		if(a[k]==0)i=i%3+1;
    	}
    	for(i=0;i<n;i++)if(a[i]==0){
    		printf("%d",i+1);break;
    	}
    }
    

    C++ :

    #include "stdio.h"
    #include "string.h"
    int main(int argc, char* argv[])
    {
    	int num[100],v[100],n,i,j,count;
    	while(~scanf("%d",&n))
    	{
    	  memset(v,0,sizeof(v));
    	 for(i=1;i<=n;i++)
    	   num[i]=i;
    	 j=1;count=0;i=1;
    	 while(i<n)
    	 {
    		if(j>n) j%=n;
    		if(v[j]==0)
    		 {
    		   count++;
    		 }
    		 if(count==3) {
    		   count=0;i++;v[j]=1;
    		 }
    		 j++;
    	 }
           for(i=1;i<=n;i++)
             if(v[i]==0)
    			 printf("%d\n",i);
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    19510
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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