1 solutions
-
0
C :
int main(int argc, char* argv[]) { int n,m,num[100],i; while(~scanf("%d",&n)) { for(i=0;i<n;i++) scanf("%d",&num[i]); scanf("%d",&m); for(i=n-m;i<n;i++) printf("%d ",num[i]); for(i=0;i<n-m;i++) printf("%d ",num[i]); } return 0; }C++ :
#include <iostream> using namespace std; int main () { int n,m; int num[500]; cin>>n; for (int i = 0;i < n; i++) cin>>num[i]; cin>>m; if (n == m) { for (int i = 0;i < n; i++) cout<<num[i]<<" "; cout<<endl; } else { for (int i = n-m;i < n; i++) cout<<num[i]<<" "; for (int i = 0;i < n-m; i++) cout<<num[i]<<" "; cout<<endl; } return 0; }
- 1
Information
- ID
- 19499
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By