1 solutions
-
0
C :
#include<stdio.h> int main() { int i,j; for(i=2;i<=1000;i++){ int sum=0; for(j=1;j<i;j++) if(i%j==0) sum=sum+j; if(sum==i) printf("%d\n",i); } return 0; }C++ :
#include <iostream> using namespace std; bool isPerfect(int n) { int sum = 1; for (int i = 2; i <=n/2;i++) { if (n%i == 0) sum+=i; } return sum == n; } int main() { for (int i =2; i<=1000; i++) { if (isPerfect(i)) cout<<i<<endl; } return 0; }Java :
public class Main{ public static void main(String[] args){ int number,chu; int sum = 0; for(number = 2;number <= 1000;number++){ for(chu = 1;chu < number;chu++){ if(number % chu == 0){ sum = sum + chu; } } if(number == sum){ System.out.println(number); } sum = 0; } } }
- 1
Information
- ID
- 19479
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By