1 solutions
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0
C :
#include <stdio.h> int main() { int n ; while( ~scanf("%d", &n) ) { if( n == 0 ) break ; double res = 0 ; for( int i = 1 ; i < n ; i ++ ) { res += 2.0*i/(n+1-i) ; } res += n ; printf("%.2lf\n", res ) ; } }C++ :
#include <cstdio> #include <cstring> using namespace std ; int main() { int T ; while( ~scanf("%d" ,&T ) ) { if( T == 0 ) break ; double res = 0 ; for( int i = 1 ; i < T ; i ++ ) { res += 2.0*i/(T+1-i) ; } res += T ; printf("%.2lf\n", res ) ; } return 0 ; }
- 1
Information
- ID
- 19439
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By