1 solutions

  • 0
    @ 2025-11-5 19:34:41

    C++ :

    #include <iostream>
    using namespace std;
    int main()
    {
    	int n,m,p;
    	cin>>n>>m>>p;
    	int i;
    	int count=0;
    //	double x1,x2, x; 
    	int x1,x2, x; 
    	for(i=1;i<m;i++)
    	{
    	//	x1=(double)n*i/m;
    	//	x2=p+(double)(n-p)*i/m;
    	//	x=x2-x1; 
    	x1=n*i/m;x2=p+(n-p)*i/m;	x=x2-x1; 
    		count+=x;
    		if((int)x2==p+(n-p)*i/m)   count--;
    		//cout<<x1<<" "<<x2<<" "<<x<<" "<<count<<endl; 
    		
    	}
    	
       cout<<count<<endl;	
    	
    	return 0;
    }
    
    • 1

    Information

    ID
    19411
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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