1 solutions

  • 0
    @ 2025-11-5 19:32:38

    C :

    #include <stdio.h>
    
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	
    	int a[n][4];
    	int i;
    	int j;
    	for(i = 0;i < n;i ++)
    	for(j = 0;j < 4;j ++)
    	scanf("%d",&a[i][j]);
    	
    	int i1,j1;
    	for(i1 = 0;i1 < n;i1 ++)
    	{
    		if((a[i1][0] == a[i1][2] && a[i1][1] == a[i1][3])||(a[i1][0] == a[i1][3] && a[i1][1] == a[i1][2]))
    		printf("YES\n");
    		
    		else
    		printf("Sorry\n");
    	}
    	return 0;
    } 
    

    C++ :

    #include<stdio.h>
    
    int main(void)
    {
        int T, a, b, m, n;
        scanf("%d", &T);
        while(T--)
        {
            scanf("%d%d%d%d", &a, &b, &m, &n);
            if((a==m&&b==n)||(b==m&&a==n))
              printf("YES\n");
            else
              printf("Sorry\n");
        }
    
        return 0;
    }
    
    

    Pascal :

    var a,b,m,n,t,i:longint;
    begin
      read(t);
      for i:=1 to t do begin
        read(a,b,m,n);
        if ((a=m)and(b=n)) or ((a=n)and(b=m)) then writeln('YES') else writeln('Sorry');
      end;
    end.
    
    • 1

    Information

    ID
    19369
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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