1 solutions
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0
C :
int main(int argc, char* argv[]) { int a; while(~scanf("%d",&a)) { printf("%d %d %d %d \n",(a/1000)%10,(a/100)%10,(a/10)%10,a%10); } return 0; }C++ :
#include <iostream> #include <cstdio> using namespace std; int main() { int a,b,c,d; int num; cin>>num; a=num/1000; b=num/100-a*10; c=num/10-a*100-b*10; d=num/1-a*1000-b*100-c*10; cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<endl; return 0; }
- 1
Information
- ID
- 19366
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By