1 solutions
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0
C :
#include <stdio.h> int main(int argc, char *argv[]) { float fact(int); int n; float sum=0; scanf("%d",&n); for(;n>0;n--) { sum+=1/fact(n); } printf("%.4f\n",sum); return 0; } float fact(int n) { float sum=1; for(;n>0;n--) { sum*=n; } return sum; }C++ :
#include<iostream> #include<cstdio> using namespace std; float fact(int n) //求阶乘 { float s=1; for (int i=1; i<=n; i++) s*=i; return s; } int main() { int n; cin>>n; float sum=0; for (int i=1; i<=n; i++) sum+=1/fact(i); printf("%.4f\n",sum); return 0; }
- 1
Information
- ID
- 19353
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
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