1 solutions

  • 0
    @ 2025-11-5 19:30:45

    C :

    #include <stdio.h>
    int main(int argc, char *argv[])
    {
    	float fact(int);
    	int n;
    	float sum=0;
    	scanf("%d",&n);
    	for(;n>0;n--)
    	{
    		sum+=1/fact(n);
    	}
    	printf("%.4f\n",sum);
    	return 0;
    }
    float fact(int n)
    {
    	float sum=1;
    	for(;n>0;n--)
    	{
    		sum*=n;
    	}
    	return sum;
    	
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    float fact(int n)	//求阶乘
    {
    	float s=1;
    	for (int i=1; i<=n; i++) s*=i;
    	return s;
    }
    int main()
    {
    	int n;
    	cin>>n;
    	float sum=0;
    	for (int i=1; i<=n; i++) sum+=1/fact(i);
    	printf("%.4f\n",sum);
    	return 0;
    }
    
    • 1

    Information

    ID
    19353
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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