1 solutions

  • 0
    @ 2025-11-5 19:30:17

    C :

    #include <stdio.h>
    #include<math.h>
    int main(int argc, char *argv[])
    {
    	float num,max=-2147483647,min=2147483648;
    	int i;
    	scanf("%d",&i);
    	for(;i>0;i--)
    	{
    		scanf("%f",&num);
    		
    		if(num>max)
    		max=num;
    		
    		if(num<min)
    		min=num;
    	}
    	
    	printf("%.2lf %.2lf\n",max,min); 
    	
    	return 0;
    }
    

    C++ :

    #include <stdio.h>
    
    int main()
    {
    	int j;
    	scanf("%d",&j);
    	float Ar[1000];
    	for (int i=0;i<j;i++)
    	{
    		scanf("%f",&Ar[i]);
    	}
    	float max=Ar[0];
    	float min=Ar[0];
    	for (int i=1;i<j;i++)
    	{
    		if (max<Ar[i])
    		{
    			max=Ar[i];
    		}
    		if (min>Ar[i])
    		{
    			min=Ar[i];
    		}
    	}
    	printf("%.2f %.2f\n",max,min);
    	return 0;
    }
    
    • 1

    Information

    ID
    19351
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
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