1 solutions

  • 0
    @ 2025-11-5 19:24:59

    C :

    #include<stdio.h>
    int main()
    {
        float a;
        scanf("%f",&a);
        printf("%6.2f\n%6.2f %6.2f\n%6.2f %6.2f %6.2f\n",a,a,a,a,a,a);
        return 0;
    }
    
    

    C++ :

    #include<cstdio>
    #define SC	scanf
    #define	PR	printf
    #define	NL	"\n"
    #define	FS	"%f"
    #define	F	"%6.2f"
    #define	F1	F NL
    #define	F2	F " " F NL
    #define	F3	F " " F " " F NL
    int main()
    {
    	float x;
    	SC(FS,&x);
    	PR(F1,x);
    	PR(F2,x,x);
    	PR(F3,x,x,x);
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题9.6

    Information

    ID
    19349
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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