1 solutions

  • 0
    @ 2025-11-5 19:23:40

    C :

    #include <stdio.h>
    int main()
    {
    int m=1,n,s=0;
    scanf("%d",&n);
    if(n==1)
    s=1;
    while(n!=1)
    { 
    	m=2*(m+1); 
    	n--;
    }
    printf("%d\n",m);
    return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
        int a=1,b,c,n;
        cin>>n;
        n--;
        while(n--)
        {
            a=(a+1)*2;
        }
        cout<<a<<endl;
    }
    
    

    Pascal :

    var s,n,i:longint;
    begin
      readln(n);
      s:=1;
      for i:=1 to n-1 do
      s:=(s+1)*2;
      writeln(s);
    end.
    
    • 1

    C语言程序设计教程(第三版)课后习题6.10

    Information

    ID
    19330
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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