1 solutions
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0
C :
#include<stdio.h> int main() { int n; double a,b,t,m,s=0; scanf("%d",&n); a=2;b=1; for(int i=0;i<n;i++) { t=a/b; s+=t; m=a; a+=b; b=m; } printf("%.2f\n",s); return 0; }C++ :
#include<stdio.h> int main() { int c=0,d,n; float a=2,b=1,sum=0,e; scanf("%d",&n); while(c<n) { sum+=a/b; e=b; b=a; a=a+e; c++; } printf("%.2f",sum); }
- 1
Information
- ID
- 19327
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By