1 solutions

  • 0
    @ 2025-11-5 19:23:28

    C :

    #include<stdio.h>
    #include<math.h>
    int he(int n)
    {
    	int s, i;
    	for(s = 1, i = 2; i <= n / 2; i++)
    	{
    		if(n % i == 0)
    			s += i;
    	}
    	return s;
    }
    int main()
    {
    	int t, i, j;
    	scanf("%d", &t);
    	for(i = 2; i <= t; i++)
    	{
    		if(i == he(i))
    		{
    			printf("%d its factors are ", i);
    			for(j = 1; j <= i / 2; j++)
    				if(i % j == 0)
    					printf("%d ", j);
    				puts("");
    		}
    	}
    }
    

    C++ :

    #include<stdio.h>
    int main()
    {
        int a,b,c,d,sum,n;
        scanf("%d",&n);
        for(b=2; b<=n; b++)
        {
            sum=0;
            for(a=1; a<b; a++)
            {
                if(b%a==0)
                    sum=sum+a;
            }
            if(sum==b)
            {
                printf("%d its factors are ",b);
                for(a=1; a<b; a++)
                    if(b%a==0)
                        printf("%d ",a);
                        printf("\n");
            }
        }
    }
    
    
    • 1

    C语言程序设计教程(第三版)课后习题6.7

    Information

    ID
    19326
    Time
    10000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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