1 solutions

  • 0
    @ 2025-11-5 19:23:25

    C :

    #include<stdio.h>
    int main()
    {
        int a,b,c,i;
        double sum=0.0;
        scanf("%d%d%d",&a,&b,&c);
        for(i=1;i<=a;i++)
            sum += (double)i;
        for(i=1;i<=b;i++)
            sum += (double)(i*i);
        //printf("%lf\n",sum);
        for(i=1;i<=c;i++)
            sum += (double)(1.0/(double)i);
        printf("%.2lf\n",sum);
        return 0;
    }
    
    

    C++ :

    #include<iostream>
    #include<stdio.h>
    using namespace std;
    int main()
    {
    	float c;
    	int a,b;
    float i,s=0,m=0,n=0;
    	cin>>a>>b>>c;
    	for( i=1;i<=a;i++)
    	{ s+=i;}
    	for(i=1;i<=b;i++)
    	{  n+=i*i;}
    	for(i=1;i<=c;i++)
    	{ m+=1/i;}
    	printf("%.2f\n",s+m+n);
      return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.5

    Information

    ID
    19325
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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