1 solutions
-
0
C :
#include<stdio.h> int main() { int a,b,c,i; double sum=0.0; scanf("%d%d%d",&a,&b,&c); for(i=1;i<=a;i++) sum += (double)i; for(i=1;i<=b;i++) sum += (double)(i*i); //printf("%lf\n",sum); for(i=1;i<=c;i++) sum += (double)(1.0/(double)i); printf("%.2lf\n",sum); return 0; }C++ :
#include<iostream> #include<stdio.h> using namespace std; int main() { float c; int a,b; float i,s=0,m=0,n=0; cin>>a>>b>>c; for( i=1;i<=a;i++) { s+=i;} for(i=1;i<=b;i++) { n+=i*i;} for(i=1;i<=c;i++) { m+=1/i;} printf("%.2f\n",s+m+n); return 0; }
- 1
Information
- ID
- 19325
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By