1 solutions
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0
C :
#include<stdio.h> #include<math.h> long long jc(int ); int main() { int a; long long sum=0ll; scanf("%d",&a); for(int i=2;i<=a;i++) sum += jc(i); printf("%lld\n",sum+1ll); return 0; } long long jc(int n) { long long sum=1; for(int i=2;i<=n;i++) sum *= (long long)i; return sum; }C++ :
#include<stdio.h> int main() { int n; long long s=0,a=1; scanf("%d",&n); for(int i=1;i<=n;i++) { a*=i; s+=a; } printf("%lld\n",s); return 0; }
- 1
Information
- ID
- 19324
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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