1 solutions

  • 0
    @ 2025-11-5 19:23:22

    C :

    #include<stdio.h>
    #include<math.h>
    long long jc(int );
    int main()
    {
        int a;
        long long sum=0ll;
        scanf("%d",&a);
        for(int i=2;i<=a;i++)
            sum += jc(i);
        printf("%lld\n",sum+1ll);
        return 0;
    }
    long long jc(int n)
    {
        long long sum=1;
        for(int i=2;i<=n;i++)
           sum *= (long long)i;
        return sum;
    }
    
    

    C++ :

    #include<stdio.h>
    int main()
    {
    	 int n;
    	 long long s=0,a=1;
    	scanf("%d",&n);
    	for(int i=1;i<=n;i++)
    	{
    	  a*=i;
    	  s+=a;
    	}
    	printf("%lld\n",s);
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.4

    Information

    ID
    19324
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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