1 solutions

  • 0
    @ 2025-11-5 19:22:52

    C :

    #include<stdio.h>
    int main()
    {
    	double f,c;
    	scanf("%lf",&f);
    	c=5*(f-32)/9;
    	printf("c=%.2f\n",c);
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    int main()
    {
        float f;
        scanf("%f",&f);
        printf("c=%.2f",5.0/9.0*(f-32));
        return 0;
    }
    
    
    • 1

    C语言程序设计教程(第三版)课后习题4.9

    Information

    ID
    19314
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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