1 solutions

  • 0
    @ 2025-11-5 19:20:54

    C :

    int main(int argc, char* argv[])
    {
    	int n,i;
    	double sum,f[100];
    	while(~scanf("%d",&n))
    	{
    		f[0]=1;f[1]=2;
    	  sum=0;
    	for(i=1;i<=n;i++)
    	{ 
    		if(i>1)
    		  f[i]=f[i-2]+f[i-1];
    		sum+=f[i]/f[i-1];
    	}
         printf("%.2lf\n",sum);
    	}
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	double fz=2,fm=1,sum=0;
    	for (int i=1; i<=n; i++)
    	{
    		sum+=fz/fm;
    		double t=fz;
    		fz+=fm;
    		fm=t;
    	}
    	printf("%.2lf\n",sum);
    	return 0;
    }
    
    • 1

    Information

    ID
    19273
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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