1 solutions
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0
C :
int main(int argc, char* argv[]) { int a,b,c,i; double sum,count; while(~scanf("%d%d%d",&a,&b,&c)) { sum=0;count=0; sum+=a*(a+1)/2.0; for(i=1;i<=b;i++) count+=i*i; sum+=count; count=0; for(i=1;i<=c;i++) count+=1.0/i; printf("%.2lf\n",sum+count); } return 0; }C++ :
#include<iostream> #include<iomanip> #include<fstream> #include<string> #include<climits> #include<cctype> #include<cmath> #include<cstring> using namespace std; int main() { //ifstream cin("aaa.txt"); int i,j,n,m,k,p,len,l,count; int c; float a,b,sum; sum=0; string s; cin>>a>>b>>c; sum+=1.0*(1+a)*a/2+1.0*b*(b+1)*(2*b+1)/6; for(i=1;i<=c;i++) { sum+=1.0/i; } cout<<fixed<<setprecision(2)<<sum; cout<<endl; return 0; }
- 1
Information
- ID
- 19240
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By