1 solutions

  • 0
    @ 2025-11-5 19:18:30

    C :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
        char o;
        int p,q,t,i,j,m,a,b,c,d,k;
        while(scanf("%d/%d%c%d/%d",&a,&b,&o,&c,&d)!=EOF)
        {
            p=b*d;
            if(o=='+')
            q=a*d+b*c;
            if(o=='-')
                q=a*d-b*c;
            if(p==q)
                printf("1\n");
            else if(q==0)
                printf("0\n");
            else if(q%p==0)
                printf("%d\n",q/p);
            else
            {
                k=q;
                if(q<0)
                    q=-q;
                else
                    q=q;
                    i=p;j=q;
                    while(i)
                    {
                        m=j%i;
                        j=i;
                        i=m;
                    }
                p=p/j;k=k/j;
                printf("%d/%d\n",k,p);
                }
             }
        return 0;
    }
    
    
    • 1

    Information

    ID
    19227
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
    # Submissions
    0
    Accepted
    0
    Uploaded By