1 solutions

  • 0
    @ 2025-11-5 19:09:48

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	for (int i=1000; i<10000; i++)
    	{
    		int a=i/100,b=i%100;
    		if (i==(a+b)*(a+b)) cout<<i<<"  ";
    	}
    	cout<<endl;
    	return 0;
    }
    
    • 1

    【C语言训练】求具有abcd=(ab+cd)2性质的四位数

    Information

    ID
    19204
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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