1 solutions
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0
C++ :
#include<iostream> #include<cmath> using namespace std; int a[10000]; int main() { int n; cin>>n; int t=sqrt(n); for (int i=1; i<=n; i++) a[i]=1; for (int i=2; i<=t; i++) //筛选法求素数表 if (a[i]) for (int j=2*i; j<=n; j+=i) a[j]=0; for (int i=2; i<=n; i++) if (a[i]) cout<<i<<endl; return 0; }
- 1
Information
- ID
- 19152
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By