1 solutions

  • 0
    @ 2025-11-5 18:57:30

    C++ :

    #include<iostream>
    #include<string>
    using namespace std;
    int main()
    {
    	string s;
    	getline(cin,s);
    	for (int i=0; s[i]!='\0'; i++)
    		if ((s[i]>='a'&&s[i]<='y') || (s[i]>='A'&&s[i]<='Y'))
    			s[i]++;
    		else if (s[i]=='z' || s[i]=='Z')
    			s[i]-=25;
    	cout<<s<<endl;
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题9.10

    Information

    ID
    19118
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    (None)
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