1 solutions

  • 0
    @ 2025-11-5 18:51:21

    C :

    #include<stdio.h>
    #define M 3
    int main()
    {
    
    	int n,a[1000],*p,*pp,i,tuichu=0,num=0;
    	p=a,pp=a;
    	scanf("%d",&n);
    	for(i=0;i<n;i++,p++)
    		*p=1;
    	p=pp;
    	while(tuichu!=n-1)
    	{
    		if(*p==1)
    			num++;
    		if(num==M)
    		{
    			*p=0,num=0,	tuichu++;
    		}
    		p++;
    		if(p==(pp+n)) p=pp;
    
    	}
        p=pp;
    	for(i=0;i<n;i++,p++)
    	{
    		if(*p==1)
    		{	printf("%d",p-pp+1);break;}
    
    	}
    
    }
    
    
    • 1

    Information

    ID
    19071
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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