1 solutions
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0
C :
#include<stdio.h> int main() { int i,N,s=1; scanf("%d",&N); for(i=N-1;i>=1;i--) s=(s+1)*2; printf("%d\n",s); return 0; }C++ :
#include<bits/stdc++.h> using namespace std; long long n,sum=1; int main() { cin>>n; for(int i=1;i<n;i++) sum=(sum+1)*2; cout<<sum; return 0; }
- 1
Information
- ID
- 19052
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
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- # Submissions
- 0
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- 0
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