1 solutions

  • 0
    @ 2025-11-5 18:48:42

    C :

    #include<stdio.h>
    int main()
    {
    	int i,M,N;
    	double s,k;
    	scanf("%d%d",&M,&N);
    	s=M; k=M*1.0/2;
    	if(N>=2)
    	{  k=k/2;
    	for(i=2;i<=N;i++)
    	{
    		s+=4*k;
    		k=k/2;
    	}
    	}
    	printf("%.2lf %.2lf\n",2*k,s);
    	return 0;
    }
    
    • 1

    Information

    ID
    19051
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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