1 solutions
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0
C :
#include<stdio.h> #include<math.h> main() { int i,a,b,c; double s=0; scanf("%d %d %d",&a,&b,&c); for(i=1;i<=a;i++) s+=i; for(i=1;i<=b;i++) s+=pow(i,2); for(i=1;i<=c;i++) s+=1.0/i; printf("%.2f\n",s); }C++ :
#include<bits/stdc++.h> using namespace std; int a,b,c; double t; int main() { cin>>a>>b>>c; t+=(1+a)*a/2; for(int i=1;i<=b;i++) t+=i*i; for(double i=1;i<=c;i++) t+=1/i; printf("%.2f",t); return 0; }
- 1
Information
- ID
- 19046
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By