1 solutions
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0
C :
#include<stdio.h> int main(void) { int x; scanf("%d",&x); if(x<1) printf("%d\n",x); else { if(x>=10) printf("%d\n",3*x-11); else printf("%d\n",2*x-1); } return 0; }C++ :
#include<bits/stdc++.h> using namespace std; int x,y; int main() { cin>>x; if(x<1)y=x; else if(1<=x&&x<10)y=2*x-1; else if(x>=10)y=3*x-11; cout<<y; return 0; }
- 1
Information
- ID
- 19039
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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