1 solutions
-
0
C :
#include <stdio.h> int main(){ int i,m,n; int a,b; int result[10],t; scanf("%d",&i); t=i; while(i--){ scanf("%d%d",&n,&m); a=(4*n-m)/2; b=(m-2*n)/2; if(a<0 || b<0 || m%2!=0) printf("No answer\n"); else printf("%d %d\n",a,b); } return 1; }C++ :
#include<iostream> using namespace std; int main() { int n,a,b,p,q; cin>>n; while(n--) { cin>>a>>b; q=(b-2*a)/2; p=a-q; if(p<0 ||q<0 || b%2) cout<<"No answer"<<endl; else cout<<p<<" "<<q<<endl; } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int a=sc.nextInt(); while(a-->0){ int n=sc.nextInt(),m=sc.nextInt(); int x=(4*n-m)/2; int y=(m-2*n)/2; if(m%2!=0||x<0||y<0){ System.out.println("No answer"); }else{ System.out.println(x+" "+y); } } sc.close(); } }
- 1
Information
- ID
- 19020
- Time
- 3000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By